In a surprising upset at the US Open, Dutch player Botic van de Zandschulp defeated Canadian star Denis Shapovalov in straight sets. The match, which took place in the fourth round of the tournament, saw van de Zandschulp outplay Shapovalov with his powerful groundstrokes and solid serving.

Van de Zandschulp, who is ranked 117th in the world, came into the match as the underdog against the 10th-seeded Shapovalov. However, he showed no signs of nerves as he took control of the match from the start. His aggressive play and ability to dictate points kept Shapovalov on the defensive throughout the match.

Shapovalov, known for his flashy shot-making and aggressive style of play, struggled to find his rhythm against van de Zandschulp. The Dutch player’s consistency and ability to absorb Shapovalov’s pace proved to be the difference in the match.

The win marks a significant milestone for van de Zandschulp, who has been making a name for himself on the ATP Tour this year. His run at the US Open has been nothing short of impressive, with wins over higher-ranked players like Casper Ruud and Diego Schwartzman.

As for Shapovalov, the loss is a disappointing end to what had been a strong season for the young Canadian. He will no doubt be looking to regroup and come back stronger in his next tournament.

Overall, van de Zandschulp’s victory over Shapovalov is a reminder of the unpredictable nature of tennis and the potential for upsets at any given moment. It will be interesting to see how far van de Zandschulp can go in the tournament and whether he can continue his impressive run against some of the top players in the world.